If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-11x^2-10+43x=0
a = -11; b = 43; c = -10;
Δ = b2-4ac
Δ = 432-4·(-11)·(-10)
Δ = 1409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-\sqrt{1409}}{2*-11}=\frac{-43-\sqrt{1409}}{-22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+\sqrt{1409}}{2*-11}=\frac{-43+\sqrt{1409}}{-22} $
| 6g-4=3g+2 | | 9+r/6-7=0 | | 9=r/6=7 | | 3x-5=7x-57 | | 4/3+3m=44/15 | | Y=-2x²+4x+6 | | 4b-15=3b+1 | | –6c+19+8=–15 | | 5/7x=24 | | c+-733=74 | | 3x+3/4=2x | | p/27=12 | | 3/4y=63/4 | | -13x-4=11-8x | | -8j=80 | | 19x=18x-20 | | -40=r-58 | | 10=t/8 | | -4(2x+5)=2(-x-9)-6 | | -31=2c-9 | | c-1.88=3.22 | | -69=9a+3 | | 9(1-2x)=-3(x-1) | | b/2=2.7 | | 17=7-2p | | Y+5=-1(-2x-3) | | -3c=48 | | 4=w/11 | | 1.9=m/3 | | -3x/2=9-2x | | x–15=42 | | d/3=2.82 |